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Question Number 150870 by liberty last updated on 16/Aug/21

Commented by mnjuly1970 last updated on 16/Aug/21

pls solve it...

plssolveit...

Answered by tabata last updated on 16/Aug/21

if the equation is given by : x^3 −2x^2 −x+2=0⇒(x+1)(x−1)(x−2)=0 ⇒x_1 =−1=a , x_2 =1=b , x_3 =2=c ∴(1/(a(b^2 +c^2 −a^2 )))+(1/(b(c^2 +a^2 −b^2 )))+(1/(c(a^2 +b^2 −c^2 ))) =−(1/4)+(1/4)−(1/4)=−(1/4) ⟨M.T ⟩

iftheequationisgivenby:x3−2x2−x+2=0⇒(x+1)(x−1)(x−2)=0⇒x1=−1=a,x2=1=b,x3=2=c∴1a(b2+c2−a2)+1b(c2+a2−b2)+1c(a2+b2−c2)=−14+14−14=−14⟨M.T⟩

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