Question and Answers Forum

All Questions      Topic List

Algebra Questions

Previous in All Question      Next in All Question      

Previous in Algebra      Next in Algebra      

Question Number 151085 by mathdanisur last updated on 18/Aug/21

Answered by talminator2856791 last updated on 18/Aug/21

$$$$$$\frac{a^2-{(a+1)}^2-{(a+2)}^2+{(a+3)}^2}{{(a+4)}^2-{(a+3)}^2-{(a+2)}^2+{(a+1)}^2}$$$$$$$$\frac{a^2-(a^2+2a+1)-(a^2+4a+4)+(a^2+6a+9)}{(a^2+8a+16)-(a^2+6a+9)-(a^2+4a+4)+(a^2+2a+1)}$$$$$$$$\frac{4}{4}=1$$$$$$

Commented by mathdanisur last updated on 18/Aug/21

$$\mathrm{Thankyou}\mathrm{Ser}$$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com