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Question Number 151104 by john_santu last updated on 18/Aug/21

Commented by john_santu last updated on 18/Aug/21

find the center of gravity with respect to point O

Answered by Olaf_Thorendsen last updated on 18/Aug/21

$$\bullet \mathrm{vertical}$$$${\mathrm{L}}_1=8\mathrm{cm}$$$${\mathrm{\Omega }}_1(0,4)$$$$$$$$\bullet \mathrm{lower}\mathrm{left}$$$${\mathrm{L}}_2=4\mathrm{cm}$$$${\mathrm{\Omega }}_2(-2,4)$$$$$$$$\bullet \mathrm{upper}$$$${\mathrm{L}}_3=6\mathrm{cm}$$$${\mathrm{\Omega }}_3(1,8)$$$$$$$$\mathrm{L}={\mathrm{L}}_1+{\mathrm{L}}_2+{\mathrm{L}}_3=8+4+6=18\mathrm{cm}$$$$$$$$\mathrm{L}\overrightarrow{\mathrm{OG}}={\mathrm{L}}_1\overrightarrow{\mathrm{O}{\mathrm{\Omega }}_1}+{\mathrm{L}}_2\overrightarrow{\mathrm{O}{\mathrm{\Omega }}_2}+{\mathrm{L}}_3\overrightarrow{\mathrm{O}{\mathrm{\Omega }}_3}$$$$\overrightarrow{\mathrm{OG}}=\frac{8}{18}(0,4)+\frac{4}{18}(-2,4)+\frac{6}{18}(1,8)$$$$\mathrm{G}=(-\frac{1}{9},\frac{16}{3})$$

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