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Question Number 151224 by mathdanisur last updated on 19/Aug/21

	Answered by Rasheed.Sindhi last updated on 19/Aug/21

	$L e t {t h e r e}^{'} r e x b o y s a n d y g i r l s$ $m i n i m u m n u m b e r o f s l i c e s e a t e n$ $= 4 x + 2 y$ $(4 s l i c e s / b o y & 2 s l i c e s / g i r l)$ $4 x + 2 y > 16 (2 c a k e s, 8 s l i c e s p e r e a c h c a k e)$ $m a x i m u m n u m b e r o f s l i c e s e a t e n$ $= 5 x + 3 y$ $(5 s l i c e s / b o y & 3 s l i c e s / g i r l)$ $5 x + 3 y < 24 (3 c a k e s)$ $4 x + 2 y > 16 \land 5 x + 3 y < 24$ $x > \frac{16 - 2 y}{4} \land x < \frac{24 - 3 y}{5}$ $\frac{16 - 2 y}{4} < x < \frac{24 - 3 y}{5}$ $y = 0 : 4 < x < 4.8 \Rightarrow x = n o v a l u e \Rightarrow y \neq 0$ $y = 1 : 3.5 < x < 4.2 \Rightarrow x = 4 ✓$ $y = 2 : 3 < x < 3.6 \Rightarrow x = n o v a l u e \Rightarrow y \neq 2$ $y = 3 : 2.5 < x < 3 \Rightarrow x = n o v a l u e \Rightarrow y \neq 3$ $y = 4 : 2 < x < 2.4 \Rightarrow x = n o v a l u e \Rightarrow y \neq 4$ $y = 5 : 1.5 < x < 1.8 \Rightarrow x = n o v a l u e \Rightarrow y \neq 5$ $y = 6 : 1 < x < 1.2 \Rightarrow x = n o v a l u e \Rightarrow y \neq 6$ $y = 7 : 0.5 < x < 0.6 \Rightarrow x = n o v a l u e \Rightarrow y \neq 7$ $y = 8 : 0 < x < 0 i m p o s s i b l e$ $(x, y) = (4, 1)$ $4 b o y s a n d 1 g i r l$
	Commented by mathdanisur last updated on 19/Aug/21

	$nice Ser thank you$
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