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Question Number 151890 by mathdanisur last updated on 23/Aug/21

Answered by mnjuly1970 last updated on 24/Aug/21

x^( 2) +y^( 2) +z^( 2) +(x^( 2) + (1/x^( 2) ))+(y^( 2) +(1/y^( 2) ) ) + ( z^( 2) +(1/z^( 2) ) ) +2 ( (x/y) +(y/z) +(z/x) ) ≥ (xy +xz +yz )+6 +6 +6=19

x2+y2+z2+(x2+1x2)+(y2+1y2)+(z2+1z2)+2(xy+yz+zx)⩾(xy+xz+yz)+6+6+6=19

Commented by mathdanisur last updated on 24/Aug/21

Thank you Ser, but = 16 or 19.?

ThankyouSer,but=16or19.?

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