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Question Number 152029 by mathdanisur last updated on 25/Aug/21

Commented by ghimisi last updated on 25/Aug/21

$${(1-4x)}^{2}or1-4x^2$$

Commented by mathdanisur last updated on 25/Aug/21

$$\mathrm{Sorry}\mathrm{dear}\mathbf{S}\mathrm{er}1-{4\mathrm{x}}^2$$

Answered by ghimisi last updated on 26/Aug/21

$$\underset{0}{\stackrel{1}{\int }}(1-4x^2)\sqrt[3]{{(4x^3-3x-1)}^2}=-\frac{1}{3}\underset{0}{\stackrel{1}{\int }}{(4x^3-3x-1)}^{{}^{\prime }}\cdot {(4x^3-3x-1)}^{\frac{2}{3}}=$$$$-\frac{1}{5}{(4x^3-3x-1)}^{\frac{5}{3}}{\mid }_0^1=-\frac{1}{5}$$

Commented by mathdanisur last updated on 26/Aug/21

$$\mathrm{Thank}\mathrm{you}\mathrm{Ser},\mathrm{but}\mathrm{ans}:-\frac{1}{5}$$

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