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Question Number 152439 by fotosy2k last updated on 28/Aug/21

Commented by fotosy2k last updated on 28/Aug/21

$$helpme$$

Commented by alisiao last updated on 29/Aug/21

$$\underset{n=1}{\sum ^{\mathrm{\infty }}}\frac{1}{\sqrt{n^5}}=\underset{n=1}{\sum ^{\mathrm{\infty }}}\frac{1}{n^{\frac{5}{2}}}\Rightarrow p=\frac{5}{2}>1$$$$isDivergentbyp-series$$$$$$

Commented by fotosy2k last updated on 30/Aug/21

$$thankyou$$

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