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Question Number 152848 by 0731619 last updated on 02/Sep/21

Commented by hknkrc46 last updated on 02/Sep/21

$$\mathit{W}\mathit{r}\mathit{o}\mathit{n}\mathit{g}!!!$$$$\sqrt{12}+\cancel{\sqrt{18}}\to \sqrt{12}+\sqrt{16}$$

Commented by hknkrc46 last updated on 02/Sep/21

Commented by mathdanisur last updated on 02/Sep/21

$$\mathrm{Nice}\mathrm{brother},\mathrm{how}\mathrm{we}\mathrm{put}\mathrm{the}\mathrm{shape}\mathrm{of}$$$$\mathrm{the}\mathrm{feathers}\mathrm{please}$$

Commented by john_santu last updated on 02/Sep/21

$$\frac{1}{\sqrt{4}+\sqrt{8}}+\frac{1}{\sqrt{8}+\sqrt{12}}+\frac{1}{\sqrt{12}+\sqrt{16}}+...+\frac{1}{\sqrt{396}+\sqrt{400}}=T$$$$T=\frac{\sqrt{8}-\sqrt{4}}{4}+\frac{\sqrt{12}-\sqrt{8}}{4}+\frac{\sqrt{16}-\sqrt{12}}{4}+...+\frac{\sqrt{400}-\sqrt{396}}{4}$$$$T=\frac{1}{4}(\sqrt{400}-\sqrt{4})=\frac{20-2}{4}=4.5$$$$$$

Commented by Tawa11 last updated on 02/Sep/21

$$\mathrm{Nice}$$

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