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Question Number 154085 by iloveisrael last updated on 14/Sep/21

Commented by iloveisrael last updated on 14/Sep/21

find area of triangle ABC

findareaoftriangleABC

Answered by EDWIN88 last updated on 14/Sep/21

let t = altitude of △ABC  ⇒arctan ((4/t))+arctan ((2/t))=(π/5)  ⇒((((6/t)))/(1−(8/t^2 ))) = tan (π/5)≈ 0.73  ⇒((6t)/(t^2 −8)) = 0.73   ⇒0.73t^2 −6t−5.84=0  ⇒t=((6+(√(36+17.05)))/(1.46)) ≈ 9.1  area of △ABC = (1/2)×6×9.1=27.3

lett=altitudeofABCarctan(4t)+arctan(2t)=π5(6t)18t2=tanπ50.736tt28=0.730.73t26t5.84=0t=6+36+17.051.469.1areaofABC=12×6×9.1=27.3

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