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Question Number 156529 by mnjuly1970 last updated on 12/Oct/21
Answered by mr W last updated on 12/Oct/21
f(+∞)→+∞f(−∞)→+∞f′(x)=4x3+6x2=2x2(2x+3)=0x=0,x=−32f(0)=−5f(−32)=8164−2×278−5=−103164f″(x)=12x2+12x=12x(x+1)=0x=0,x=−1⇒2realroots:one>0,one<−32
Commented by mr W last updated on 12/Oct/21
Commented by mnjuly1970 last updated on 12/Oct/21
gratefulsirW
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