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Question Number 157769 by Study last updated on 27/Oct/21

Commented by Study last updated on 27/Oct/21

$$whatisthepracticeandsolve?$$

Commented by mr W last updated on 27/Oct/21

$$1.1^n=2$$$$n=\frac{\log 2}{\log 1.1}\approx 7.3years$$

Commented by Study last updated on 28/Oct/21

$$pleasehelpemy[$$

Commented by Study last updated on 28/Oct/21

$$canwesolveitbysimpleintersectformula?$$

Commented by mr W last updated on 28/Oct/21

$$P{(1+\frac{10}{100})}^n=2P$$$$1.1^n=2$$$$\Rightarrow n=\frac{\log 2}{\log 1.1}$$$${that}^{\prime }sall.$$

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