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Question Number 158313 by mnjuly1970 last updated on 02/Nov/21

Answered by mr W last updated on 02/Nov/21

α,β,γ are angles of a triangle. F=((sin α cos α+sin β cos β+sin γ cos γ)/(sin α sin β sin γ)) F=((sin 2α+sin 2β+sin 2γ)/(2 sin α sin β sin γ)) F=((4 sin α sin β sin γ)/(2 sin α sin β sin γ)) F=2

α,β,γareanglesofatriangle.F=sinαcosα+sinβcosβ+sinγcosγsinαsinβsinγF=sin2α+sin2β+sin2γ2sinαsinβsinγF=4sinαsinβsinγ2sinαsinβsinγF=2

Commented by mnjuly1970 last updated on 02/Nov/21

thx mr W

thxmrW

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