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Question Number 159157 by physicstutes last updated on 13/Nov/21

Answered by mr W last updated on 13/Nov/21

Commented by mr W last updated on 13/Nov/21

$$let{AA}^{\prime }=1$$$$\Rightarrow {BB}^{\prime }=\frac{50}{450}\times 1=\frac{1}{9}$$$$\Rightarrow {CC}^{\prime }={BB}^{\prime }=\frac{1}{9}$$$$\Rightarrow {DD}^{\prime }=\frac{75}{300+75}\times \frac{1}{9}=\frac{1}{45}$$$$P\times 1=9\times \frac{1}{45}$$$$\Rightarrow P=\frac{1}{5}KN$$$$M_D=\frac{1}{5}\times (450+50+300)$$$$=160KNmm=160Nm$$

Commented by Tawa11 last updated on 13/Nov/21

$$\mathrm{Great}\mathrm{sir}.$$

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