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Question Number 15987 by b.e.h.i.8.3.4.1.7@gmail.com last updated on 16/Jun/17

Commented by b.e.h.i.8.3.4.1.7@gmail.com last updated on 16/Jun/17

$$H,isapointoncirclewithcenterpoint:A.$$$$provethat:$$$$\mathrm{\angle }DHF={135}^{\bullet }.$$

Answered by ajfour last updated on 16/Jun/17

$$\mathrm{\angle }DHF=\frac{1}{2}\left(reflex\mathrm{\angle }DAF\right)$$$$=\frac{1}{2}\left(270°\right)=135°.$$

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