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Question Number 160950 by geron last updated on 09/Dec/21

Answered by mindispower last updated on 09/Dec/21

$$y=\frac{2x}{1-x^2},x=\frac{2z}{1-z^2},z=\frac{2y}{1-y^2}$$$$justx=tg\left(a\right),y=tg\left(b\right),z=tg\left(c\right)$$$$withetg\left(2t\right)=\frac{2tg\left(t\right)}{1-{tg}^2\left(t\right)}$$

Commented by geron last updated on 10/Dec/21

$$thankyou$$

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