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Question Number 16108 by Joel577 last updated on 18/Jun/17

Commented by Joel577 last updated on 18/Jun/17

$$\mathrm{How}\mathrm{to}\mathrm{find}\mathrm{\angle }PAD?$$

Answered by ajfour last updated on 18/Jun/17

Commented by ajfour last updated on 18/Jun/17

$$2\theta +2\theta +\theta =180°$$$$\Rightarrow \theta =36°$$$$?+?+(90-36°)=180°$$$$?=\frac{90°+36°}{2}=63°.$$

Commented by ajfour last updated on 18/Jun/17

$$theyarebothradiusofthe$$$$semicirclebecauseitookpoint$$$$Ptobethecentreofthesemicircle.$$

Commented by Joel577 last updated on 18/Jun/17

$$\mathrm{How}\mathrm{did}\mathrm{u}\mathrm{know}\mathrm{that}DP\mathrm{and}CP$$$$\mathrm{have}\mathrm{same}\mathrm{length}?$$

Commented by Joel577 last updated on 18/Jun/17

$$thankyouverymuch$$

Commented by Joel577 last updated on 23/Jun/17

$$\mathrm{one}\mathrm{more},\mathrm{why}\mathrm{\angle }P\mathrm{is}2\theta ?$$

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