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Question Number 161150 by mathlove last updated on 13/Dec/21

Commented by MJS_new last updated on 13/Dec/21

y=(√(2x^2 ))≥0 y=(√2)∣x∣ ⇒ xy=(√2)∣x∣x= { ((x<0; −(√2)x^2 )),((x≥0; (√2)x^2 )) :}

y=2x2⩾0y=2∣x∣⇒xy=2∣x∣x={x<0;−2x2x⩾0;2x2

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