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Question Number 161444 by cortano last updated on 18/Dec/21
Commented by blackmamba last updated on 18/Dec/21
f(x)=3x−4⇒f(2016)=6044
f(x)=ax+bf(x2+x)=ax2+ax+b2f(x2−3x+2)=2[(ax2−3ax+2a)+b]f(x)+2f(x2−3x+2)=3ax2−5ax+4a+3b{3a=9⇒a=34a+3b=0⇒3b=−12;b=−4∴f(x)=3x−4⇒f(2016)=60443×2016−46044.0
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