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Question Number 162496 by cortano last updated on 29/Dec/21

Answered by mr W last updated on 30/Dec/21

Commented by mr W last updated on 30/Dec/21

$$\mathrm{\angle }DCB=90-15=75°=\alpha$$$$\alpha =2\beta$$$$\mathrm{\angle }FDE=\beta =\frac{75°}{2}$$$$\mathrm{\angle }AEG=\mathrm{\angle }FDE=\frac{75°}{2}$$$$\mathrm{\angle }GAE=30°+15°=45°$$$$x=\mathrm{\angle }AEG+\mathrm{\angle }GAE=\frac{75°}{2}+45°=82.5°$$

Commented by Tawa11 last updated on 30/Dec/21

$$\mathrm{Great}\mathrm{sir}$$

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