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Question Number 162701 by mnjuly1970 last updated on 31/Dec/21

Answered by phanphuoc last updated on 31/Dec/21

$$\varphi (a,b)={\int }_0^1{x}^a{(1-x^2)}^{b}dx=1/2B((a+1)/2,(2b+1)/2)$$$${\partial }^2\left(\varphi \right)/\partial \left(a^2\right)\partial \left(b^2\right)=.....$$$$a=-2,b=1$$

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