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Question Number 16466 by tawa tawa last updated on 22/Jun/17

Answered by sandy_suhendra last updated on 22/Jun/17

Commented by sandy_suhendra last updated on 22/Jun/17

$${\mathrm{n}}_1=\mathrm{the}\mathrm{refractive}\mathrm{index}\mathrm{of}\mathrm{water}=\frac{4}{3}$$$${\mathrm{n}}_2=\mathrm{the}\mathrm{refractive}\mathrm{index}\mathrm{of}\mathrm{air}=1$$$${\mathrm{n}}_1\sin \mathrm{i}={\mathrm{n}}_2\sin \mathrm{r}$$$$\frac{4}{3}\sin \mathrm{i}=1\sin 90°$$$$\sin \mathrm{i}=\frac{3}{4}\Rightarrow \mathrm{i}=48.6°$$$$$$$$\tan \mathrm{i}=\frac{\frac{1}{2}\mathrm{d}}{2}$$$$\tan 48.6°=\frac{1}{4}\mathrm{d}$$$$\mathrm{d}=4\times \tan 48.6=4.54\mathrm{m}$$

Commented by tawa tawa last updated on 22/Jun/17

$$\mathrm{God}\mathrm{bless}\mathrm{you}\mathrm{sir}.\mathrm{i}\mathrm{appreciate}.$$

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