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Question Number 164672 by mathlove last updated on 20/Jan/22
Answered by Ar Brandon last updated on 20/Jan/22
Ω=∫0πcosx+13+4cosx+cos2xdx=∫0πcosx+1(cosx+1)(cosx+3)dx=∫0πcosx+1cosx+3dx=2∫0πcos(x2)4−2sin2(x2)dx=2∫0π2cosx2−sin2xdx=2[arcsin(sinx2)]0π2=2(π4)=π2
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