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Question Number 166928 by amin96 last updated on 02/Mar/22

Answered by mr W last updated on 02/Mar/22

a picture says more than a thousant  words...

apicturesaysmorethanathousantwords...

Commented by mr W last updated on 03/Mar/22

Commented by mr W last updated on 03/Mar/22

ECDH is cyclic,   ⇒blue angle ∠HDE=∠HCE=α  similarly  ⇒red angle ∠HDF=∠HBF=β  ΔBFH∼ΔCEH  ⇒∠HBF=∠HCE  ⇒∠HDF=∠HDE

ECDHiscyclic,blueangleHDE=HCE=αsimilarlyredangleHDF=HBF=βΔBFHΔCEHHBF=HCEHDF=HDE

Commented by som(math1967) last updated on 03/Mar/22

∠HDE=∠HCE=α  ∠HBF=∠HBF=β  again B,C,E,F also cyclic  ∴ ∠EBF=∠ECF  ∴β=α

HDE=HCE=αHBF=HBF=βagainB,C,E,FalsocyclicEBF=ECFβ=α

Commented by Tawa11 last updated on 03/Mar/22

Great sir

Greatsir

Commented by Tawa11 last updated on 03/Mar/22

Great sir

Greatsir

Commented by otchereabdullai@gmail.com last updated on 21/Mar/22

nice!

nice!

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