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Question Number 168942 by Tawa11 last updated on 21/Apr/22

Commented by mr W last updated on 21/Apr/22

$$(m_g+m_b+m_s)v_1=(m_g+m_b)v_{2b}+m_s{v}_{2s}$$$$v_{2b}=\frac{(m_g+m_b+m_s)v_1-m_s{v}_{2s}}{m_g+m_b}$$$$=\frac{(50+0.5)\times 5-0.5\times 15}{50}=4.9m/s$$

Commented by Tawa11 last updated on 21/Apr/22

$$\mathrm{Wow},\mathrm{God}\mathrm{bless}\mathrm{you}\mathrm{sir}.$$

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