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Question Number 169480 by TOTTI last updated on 01/May/22
Answered by MikeH last updated on 01/May/22
(a)limx→1−g(x)=limx→1x=1(b)limx→1+g(x)=limx→1(2−x2)=1∴limx→1g(x)=1(c)g(1)=3(d)limx→2−g(x)=limx→2(2−x2)=−2(e)limx→2+g(x)=limx→2(x−3)=−1hencelimx→2g(x)doesnotexist.
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