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Question Number 171493 by Mastermind last updated on 16/Jun/22

	Answered by mr W last updated on 16/Jun/22

	$A = 4 \times s h a d e d t r i a n g l e + 1 \times s q u a r e$ $A = 4 \times \frac{2 \times 3 \times \sqrt{2}}{2 \times 2} + (2^{2} + 3^{2} + 2 \times 2 \times 3 \times \frac{\sqrt{2}}{2})$ $A = 13 + 12 \sqrt{2}$
	Commented by mr W last updated on 16/Jun/22

	Commented by Mastermind last updated on 16/Jun/22

	$I s t h i s a d i a g r a m t o t h e q u e s t i o n ?$
	Commented by mr W last updated on 16/Jun/22

	$y e s .$ $w h y s h o u l d i d o i t i f i t h a s n o t h i n g t o$ $d o w i t h t h e q u e s t i o n .$
	Commented by mr W last updated on 17/Jun/22

	${l e t}^{'} s l o o k a t a n - s i d e - p o l y g o n$ $i n s c r i b e d i n a c i r c l e . t h e s i d e s$ $l e n g t h e s a r e a_{1}, a_{2}, . . . a_{i}, . . . a_{n} . s a y t h e$ $r a d i u s i s R . w e s e e t h a t t h e a r e a o f t h e$ $p o l y g o n i s t h e s u m o f a l l n t r i a n g l e s$ $w i t h s i d e s R, a_{i}, R . o n l y t h e s u m o f$ $t h e n t r i a n g l e s i s i m p o r t a n t, t h e o r d e r$ $o f t h e n t r i a n g l e s {d o e s n}^{'} t m a t t e r .$ $i . e . w e c a n r e a r r a n g e t h e n s i d e s$ $a r b i t r a r i l y w i t h o u t c h a n g i n g t h e a r e a$ $o f t h e i n s c r i b e d p o l y g o n .$
	Commented by mr W last updated on 16/Jun/22

	$u s u a l l y i {d o n}^{'} t s h o w e v e r y s t e p w h e n$ $i t r y t o s o l v e a p r o b l e m . c e r t a i n l y i$ $k n o w t h a t t h e q u e s t i o n s a y s ‘ ‘ f o u r$ $c o n s e c u t i v e s i d e s o f l e n g t h 3 a n d f o u r$ $c o n s e c u t i v e s i d e s o f l e n g t h 2^{″} . b u t f o r$ $a p o l y g o n i n s c r i b e d i n a c i r c l e, i t s$ $a r e a i s i n d e p e n d e n t i n w h i c h o r d e r$ $i t s s i d e s a r e a r r a n g e d . t h e r e f o r e i$ $r e a r r a n g e d t h e o r d e r o f t h e s i d e s s o$ $t h a t i t s a r e a c a n b e e a s i l y c a l c u l a t e d .$
	Commented by mr W last updated on 16/Jun/22

	Commented by Mastermind last updated on 17/Jun/22

	$O k a y$ $t h a n k s b i g b o s s$
	Commented by Tawa11 last updated on 17/Jun/22

	$Great sir .$
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