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Question Number 171666 by Mastermind last updated on 19/Jun/22

Commented by kaivan.ahmadi last updated on 19/Jun/22

3^x +log_2 x=10⇒log_2 2^3^x +log_2 x=10⇒ x×2^3^x =2^(10) ⇒x=2^y 2^(y+3^2^y ) =2^(10) ⇒y+3^2^y =10=1+3^2 2^y =2⇒y=1⇒x=2

3x+log2x=10⇒log223x+log2x=10⇒x×23x=210⇒x=2y2y+32y=210⇒y+32y=10=1+322y=2⇒y=1⇒x=2

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