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Question Number 172918 by mnjuly1970 last updated on 03/Jul/22

Commented by som(math1967) last updated on 03/Jul/22

yes i got ((16)/3)cm

yesigot163cm

Commented by infinityaction last updated on 03/Jul/22

((16)/3) ???

163???

Commented by som(math1967) last updated on 03/Jul/22

Commented by som(math1967) last updated on 03/Jul/22

AE∥PQ∥BC  △ADQ∼△ACB   ∴((DQ)/(BC))=((AQ)/(AB))=(4/(12))=(1/3)  ⇒DQ=(1/3)BC=(8/3)   PD=(2/3)AE=(8/3)  ∴PQ=(8/3)+(8/3)=((16)/3)cm

AEPQBCADQACBDQBC=AQAB=412=13DQ=13BC=83PD=23AE=83PQ=83+83=163cm

Commented by mnjuly1970 last updated on 03/Jul/22

excellent sir

excellentsir

Commented by Tawa11 last updated on 03/Jul/22

Great sir

Greatsir

Commented by infinityaction last updated on 04/Jul/22

Commented by infinityaction last updated on 04/Jul/22

AF = 12 and EF  =  8  △ADF ∼ APE    ((PE)/4) = (4/(12))   ⇒ PE = (4/3)  PQ = PE + EQ  PQ = (4/3)+4 = ((16)/3)

AF=12andEF=8ADFAPEPE4=412PE=43PQ=PE+EQPQ=43+4=163

Commented by Tawa11 last updated on 06/Jul/22

Great sir

Greatsir

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