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Question Number 174303 by dragan91 last updated on 29/Jul/22

Answered by a.lgnaoui last updated on 29/Jul/22

x^2 −10x−ax+10a+1=x^2 +cx+bx+bc x^2 −(10+a)x+10a+1=x^2 +(b+c)x+bc −(10+a)=b+c 10a+1 =bc b,c verifie l equation: z^2 −(10+a)z+10a+1=0 Δ=(10+a)^2 −4(10a+1) =a^2 −20a+96=(a−12)(a−8) •a=8 b+c =−18 bc=81 z^2 +18z+81=(z+9)^2 donc a=8;b=c=−9 •a=12 b+c=−22 bc=121 z^2 +22z+121=(z+11)^2 donc a=12; b=c=−11

x2−10x−ax+10a+1=x2+cx+bx+bcx2−(10+a)x+10a+1=x2+(b+c)x+bc−(10+a)=b+c10a+1=bcb,cverifielequation:z2−(10+a)z+10a+1=0Δ=(10+a)2−4(10a+1)=a2−20a+96=(a−12)(a−8)∙a=8b+c=−18bc=81z2+18z+81=(z+9)2donca=8;b=c=−9∙a=12b+c=−22bc=121z2+22z+121=(z+11)2donca=12;b=c=−11

Commented by Tawa11 last updated on 29/Jul/22

Great sir

Greatsir

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