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Question Number 174533 by mnjuly1970 last updated on 03/Aug/22
Answered by behi834171 last updated on 03/Aug/22
x2=2x+1⇒x2−2x−1=0⇒{α+β=2α.β=−1x3=2x2+x=5x+2x4=5x2+2x=10x+5+2x=12x+5x5=12x2+5x=24x+12+5x=29x+12x6=29x2+12x=58x+29+12x=70x+29x7=70x2+29x=140x+70+29x=169x+70⇒A=(2α+1).(169β+70)+15(2α+1)+β+3==338αβ+140α+169β+70+30α+15+β+3==338αβ+170(α+β)+88==−338×1+170×2+88=90.◼
Commented by Rasheed.Sindhi last updated on 03/Aug/22
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