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Question Number 176891 by Shrinava last updated on 27/Sep/22

Answered by mr W last updated on 27/Sep/22

sin x cos 3x (1/2)=2 sin x cos x (((cos x)/2)+(((√3) sin x)/2))(((cos x)/2)−(((√3) sin x)/2)) cos 3x = cos x (cos^2 x−3 sin^2 x) 4 cos^2 x−3 = cos^2 x−3 sin^2 x 3−3 =0 0=0 ✓ ⇒any x fulfills the equation and is a solution.

sinxcos3x12=2sinxcosx(cosx2+3sinx2)(cosx2−3sinx2)cos3x=cosx(cos2x−3sin2x)4cos2x−3=cos2x−3sin2x3−3=00=0✓⇒anyxfulfillstheequationandisasolution.

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