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Question Number 177848 by mathdave last updated on 09/Oct/22

Commented by mathdave last updated on 09/Oct/22

$$mrwhelpmeoutooorothers$$

Commented by mr W last updated on 10/Oct/22

$$ihopesomeoneelsecouldhelpyou.$$

Commented by York12 last updated on 22/May/23

$$youareuploadingyourassigmentsonthe$$$$forum$$$$andharryingusuptosolvethem$$$$youarestupidorsimplylazy$$

Answered by Spillover last updated on 10/Oct/22

$$\sin \left(\frac{\mathrm{A}+\partial \mathrm{m}}{2}\right)=\cot \frac{\mathrm{A}}{2}\sin \frac{\mathrm{A}}{2}$$$$\sin \left(\frac{\mathrm{A}+\partial \mathrm{m}}{2}\right)=\frac{\cos \frac{\mathrm{A}}{2}}{\sin \frac{\mathrm{A}}{2}}\sin \frac{\mathrm{A}}{2}$$$$\sin \left(\frac{\mathrm{A}+\partial \mathrm{m}}{2}\right)=\cos \frac{\mathrm{A}}{2}=\sin (\frac{\pi }{2}-\frac{\mathrm{A}}{2})$$$$\frac{\mathrm{A}+\partial \mathrm{m}}{2}=\frac{\pi }{2}-\frac{\mathrm{A}}{2}$$$$\partial \mathrm{m}=\pi -2\mathrm{A}$$$$$$

Commented by mathdave last updated on 10/Oct/22

$$thankssirireallyappreciate$$

Answered by Spillover last updated on 10/Oct/22

$$\frac{1.55}{1.30}=\frac{\sin \left(\frac{\mathrm{A}+\mathrm{D}}{2}\right)}{\sin \frac{\mathrm{A}}{2}}=\frac{\sin \left(\frac{65+\mathrm{D}}{2}\right)}{\sin \frac{65}{2}}$$$$\frac{1.55}{1.30}=\frac{\sin \left(\frac{65+\mathrm{D}}{2}\right)}{\sin \frac{65}{2}}$$$$\mathrm{Find}\mathrm{D}\uparrow \uparrow$$$$$$

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