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Question Number 178940 by ARUNG_Brandon_MBU last updated on 22/Oct/22

Answered by mr W last updated on 23/Oct/22

Commented by mr W last updated on 23/Oct/22

ΔGEA≡ΔCED  ⇒[ABCD]=[ΔGBC]  CB=34+8.5=42.5  CG=2×16=32  cos α=((16^2 +34^2 −30^2 )/(2×16×34))=(8/(17))  ⇒sin α=(√(1−((8/(17)))^2 ))=((15)/(17))  [ΔGBC]=((CG×CB×sin α)/2)      =((32×42.5×15)/(17×2))=600 ✓

ΔGEAΔCED[ABCD]=[ΔGBC]CB=34+8.5=42.5CG=2×16=32cosα=162+3423022×16×34=817sinα=1(817)2=1517[ΔGBC]=CG×CB×sinα2=32×42.5×1517×2=600

Commented by Ar Brandon last updated on 23/Oct/22

Thank you Sir

Commented by Tawa11 last updated on 23/Oct/22

Great sir

Greatsir

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