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Question Number 179631 by daus last updated on 31/Oct/22

Commented by daus last updated on 31/Oct/22

$s o l v e f o r x$
	Answered by Rasheed.Sindhi last updated on 31/Oct/22

	$64^{4 x} = {(\frac{1}{4})}^{3 x}$ $4^{12 x} . 4^{3 x} = 1$ $4^{15 x} = 4^{0}$ $15 x = 0$ $x = 0$
	Commented by daus last updated on 31/Oct/22

	$t h a n k s$
	Answered by Acem last updated on 01/Nov/22

	$64^{4 x} = 0 . 25^{3 x}$ $12 x \ln 4 = - 3 x \ln 4$ $15 x \ln 4 = 0 \Rightarrow x = 0$
	Answered by Rasheed.Sindhi last updated on 01/Nov/22
	$64^(4x) =((1/4))^(3x) =4^(−3x) ={(4^3 )^(1/3) }^(−3x) =64^(−3x) ⇒4x=−3x⇒12x=0⇒x=0$
	$64^{4 x} = {(\frac{1}{4})}^{3 x} = 4^{- 3 x} = {{(4^{3})}^{\frac{1}{3}}}^{- 3 x} = 64^{- 3 x}$ $\Rightarrow 4 x = - 3 x \Rightarrow 12 x = 0 \Rightarrow x = 0$
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