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Question Number 180858 by Mastermind last updated on 18/Nov/22

Answered by mr W last updated on 18/Nov/22

A=2×((a×a×tan [(1/2)((π/2)−α)])/2)     =a^2 tan ((π/4)−(α/2))

A=2×a×a×tan[12(π2α)]2=a2tan(π4α2)

Commented by Mastermind last updated on 18/Nov/22

With full details explanation boss

Withfulldetailsexplanationboss

Commented by mr W last updated on 18/Nov/22

Commented by mr W last updated on 18/Nov/22

2β+α=(π/2)  ⇒α=(π/4)−(α/2)  b=a tan α=a tan ((π/4)−(α/2))  (A/2)=((ab)/2)=((a×a tan ((π/4)−(α/2)))/2)  ⇒A=a^2 tan ((π/4)−(α/2))

2β+α=π2α=π4α2b=atanα=atan(π4α2)A2=ab2=a×atan(π4α2)2A=a2tan(π4α2)

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