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Question Number 182437 by akolade last updated on 09/Dec/22
Answered by qaz last updated on 09/Dec/22
(n+2r)=[xr](1+x)n+2=[xr]((1+x)n+2x(1+x)n+x2(1+x)n)=[xr](1+x)n+2[xr−1](1+x)n+[xr−2](1+x)n=(nr)+2(nr−1)+(nr−2),byegorychev′smethod
Commented by akolade last updated on 17/Dec/22
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