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Question Number 182582 by sciencestudent last updated on 11/Dec/22

	Answered by Acem last updated on 11/Dec/22

	$a ∙ M a t h e m a t i c a l m e t h o d :; D i s t a n c e = v . t$ $80 = 2 \times 2 \times 4 \times 5; d i f f . o f t i m e = 1 h r w e t a k e 4, 5$ $80 = 4 \times 20 = 5 \times 16$ $d a i l y : v = 16 k m / h r$ $t h i s d a y : v = 20 k m / h r$
	Answered by Acem last updated on 11/Dec/22

	$b ∙ P h i s i c a l m e t h o d$ $D i s t a n c e = v . t = v^{'} . t^{'} = (v + 4) . (t - 1)$ $v . t = v . t - v + 4 (t - 1)$ $v = 4 (t - 1)$ $\frac{d i s .}{t} = 4 (t - 1); d i s . = 80$ $20 = t (t - 1)$ $t_{s 1} = - 4 t_{s 2} = 5 h r$ $v = 16 k m / h r^{'} n o r m a l d a y s$ $v^{'} = 20 k m / h r; t^{'} = 4 h r^{'} t h i s d a y$
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