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Question Number 18492 by virus last updated on 22/Jul/17

Commented by mrW1 last updated on 23/Jul/17

$$\mathrm{the}\mathrm{force}\mathrm{in}\mathrm{k}\mathrm{above}\mathrm{block}\mathrm{A}\mathrm{is}3\mathrm{mg}.$$$$\mathrm{when}\mathrm{the}\mathrm{spring}\mathrm{above}\mathrm{A}\mathrm{is}\mathrm{cut},\mathrm{this}$$$$\mathrm{force}\mathrm{is}\mathrm{released},\mathrm{a}\mathrm{force}\mathrm{of}3\mathrm{mg}\mathrm{is}$$$$\mathrm{acting}\mathrm{on}\mathrm{block}\mathrm{A},\mathrm{therefore}{\mathrm{a}}_{\mathrm{A}}=3\mathrm{g}.$$$$$$$$\mathrm{block}\mathrm{B}\mathrm{and}\mathrm{C}\mathrm{are}\mathrm{still}\mathrm{in}\mathrm{equilibrium},$$$$\mathrm{therefore}{\mathrm{a}}_{\mathrm{B}}={\mathrm{a}}_{\mathrm{C}}=0.$$

Answered by mrW1 last updated on 23/Jul/17

$${\mathrm{a}}_{\mathrm{B}}={\mathrm{a}}_{\mathrm{C}}=0$$$${\mathrm{a}}_{\mathrm{A}}=3\mathrm{g}$$

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