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Question Number 185705 by Mingma last updated on 26/Jan/23

Answered by mr W last updated on 26/Jan/23

$$s=\frac{n-1+n+n+1}{2}=\frac{3n}{2}$$$$\stackrel{\mathrm{\_}}{r}=\frac{rs}{s-n}=\frac{r}{1-\frac{n}{s}}=\frac{r}{1-\frac{2n}{3n}}=3r$$$$\frac{r}{\stackrel{\mathrm{\_}}{r}}=\frac{1}{3}✓$$

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