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Question Number 18593 by Joel577 last updated on 25/Jul/17
Answered by 433 last updated on 25/Jul/17
2016(12015n2014+22015n2014...+n)−n22016(12014n2014+22014n2014+...+n2014n2014)2016n−n2→−∞2016(0+0+...+0)−∞2016(0+0+...+1)=−∞
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