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Question Number 188128 by Rupesh123 last updated on 26/Feb/23

Answered by mr W last updated on 26/Feb/23

WLG, assume a≤b≤c. cos C=((a^2 +b^2 −c^2 )/(2ab)) 2b×cos C=((a^2 +b^2 −c^2 )/a)=a+((b^2 −c^2 )/a)≤a

WLG,assumea⩽b⩽c.cosC=a2+b2−c22ab2b×cosC=a2+b2−c2a=a+b2−c2a⩽a

Commented by Rupesh123 last updated on 26/Feb/23

Nice!

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