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Question Number 190874 by Rupesh123 last updated on 13/Apr/23

Answered by cortano12 last updated on 13/Apr/23

$$\left(1\right){26}^2={(\mathrm{a}+\mathrm{t})}^2+{\mathrm{t}}^2$$$$\left(2\right){20}^2={(\mathrm{a}-\mathrm{t})}^2+{\mathrm{t}}^2$$$$\Rightarrow 46.6=\left(2\mathrm{a}\right)\left(2\mathrm{t}\right)\Rightarrow 2\mathrm{at}=46.3$$$$\Rightarrow \mathrm{area}\mathrm{\Delta }\mathrm{ABC}=\frac{1}{2}.2\mathrm{a}.\mathrm{t}=23\times 3=69$$

Commented by Rupesh123 last updated on 13/Apr/23

Excellent, sir!

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