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Question Number 190878 by 073 last updated on 13/Apr/23

Answered by HeferH last updated on 13/Apr/23

$$\frac{\mathrm{a}}{\mathrm{b}}=\frac{\mathrm{c}}{\mathrm{d}}=\frac{\mathrm{e}}{\mathrm{f}}=\mathrm{k}$$$$\mathrm{a}=\mathrm{bk}$$$$\mathrm{e}=\mathrm{fk}$$$$\mathrm{c}=\mathrm{dk}$$$$\frac{{\mathrm{bfk}}^2+{\mathrm{d}}^2{\mathrm{k}}^2}{\mathrm{bf}+{\mathrm{d}}^2}={\mathrm{k}}^2\left(\frac{\mathrm{bf}+{\mathrm{d}}^2}{\mathrm{bf}+{\mathrm{d}}^2}\right)={\mathrm{k}}^2\times 1={\mathrm{k}}^2$$

Commented by 073 last updated on 13/Apr/23

$$\mathrm{nice}$$

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