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Question Number 191403 by Mingma last updated on 23/Apr/23

Answered by mr W last updated on 23/Apr/23

as Q191305 but θ=45°  r=((ab)/(a+b+(√(a^2 +b^2 ))+(a+(√3)b)sin θ+((√3)a+b)cos θ))  with θ=45°  r=((ab)/( (√(a^2 +b^2 ))+(1+((1+(√3))/( (√2))))(a+b)))  with a=12, b=5:  r=((60)/( 30+((17(1+(√3)))/( (√2)))))≈0.955

asQ191305butθ=45°r=aba+b+a2+b2+(a+3b)sinθ+(3a+b)cosθwithθ=45°r=aba2+b2+(1+1+32)(a+b)witha=12,b=5:r=6030+17(1+3)20.955

Commented by mr W last updated on 23/Apr/23

Commented by Mingma last updated on 23/Apr/23

Excellent, sir!

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