Question and Answers Forum

All Questions      Topic List

None Questions

Previous in All Question      Next in All Question      

Previous in None      Next in None      

Question Number 19615 by icyfalcon999 last updated on 13/Aug/17

Answered by Tinkutara last updated on 13/Aug/17

$$\frac{1}{4}\underset{-\mathrm{\infty }}{\stackrel{\mathrm{\infty }}{\int }}\frac{dx}{x^2+{\left(\frac{1}{2}\right)}^2}=\frac{1}{2}{\left[{\tan }^{-1}2x\right]}_{-\mathrm{\infty }}^{\mathrm{\infty }}$$$$=\frac{1}{2}[\frac{\pi }{2}-(-\frac{\pi }{2})]=\frac{\pi }{2}$$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com