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Question Number 196619 by universe last updated on 28/Aug/23

Answered by cortano12 last updated on 28/Aug/23

$$\mathrm{f}(\mathrm{x}+\sqrt{{\mathrm{x}}^2+1})=-\frac{1}{\mathrm{x}+\sqrt{{\mathrm{x}}^2+1}}$$$$\mathrm{f}\left(\mathrm{x}\right)=-\frac{1}{\mathrm{x}}$$$$\mathrm{f}\left(2\right)+\mathrm{f}\left(3\right)+\mathrm{f}\left(6\right)=-(\frac{1}{2}+\frac{1}{3}+\frac{1}{6})=\overline{)\begin{array}{c}-1\end{array}}$$$$$$

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