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Question Number 196635 by sonukgindia last updated on 28/Aug/23
Answered by sniper237 last updated on 28/Aug/23
=∑∞n=0(−1)nf(n);f(z)=1(2z+1)3=Residutheoapplicat%Res(πf(z)sin(πz);−1/2)=d3dz3(π8sin(πz))∣z=−1/2
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