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Question Number 196725 by sonukgindia last updated on 30/Aug/23

Answered by Frix last updated on 30/Aug/23

(c) t^8 +(1/t^8 )=m t^8 +(1/t^8 )+2=m+2 (t^4 +(1/t^4 ))^2 =m+2 t^4 +(1/t^4 )=(√(m+2)) Same procedure again.. t^4 +(1/t^4 )+2=(√(m+2))+2 t^2 +(1/t^2 )=(√((√(m+2))+2)) ...and again t+(1/t)=(√((√((√(m+2))+2))+2))

(c)t8+1t8=mt8+1t8+2=m+2(t4+1t4)2=m+2t4+1t4=m+2Sameprocedureagain..t4+1t4+2=m+2+2t2+1t2=m+2+2...andagaint+1t=m+2+2+2

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