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Question Number 196914 by SANOGO last updated on 03/Sep/23
Answered by witcher3 last updated on 03/Sep/23
−1n+1>−1nIn=[−1n,1]In+1⊆InsuitedecroissanteminoreDouble subscripts: use braces to clarifyDouble subscripts: use braces to clarify∪n⩾In=I1=]−1,1]
Answered by aleks041103 last updated on 04/Sep/23
∀n⩾1,[0,1]⊂[−1n,1]⇒[0,1]⊂∩n⩾1[−1n,1]letr<0.ThenexistsN∈N,s.t.1N<−r⇒r<−1N⇒r∉[−1N,1].⇒∀r<0,r∉∩n⩾1[−1n,1]⇒∩n⩾1[−1n,1]=[0,1]Theotherisanalogous.
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