Question and Answers Forum

All Questions      Topic List

None Questions

Previous in All Question      Next in All Question      

Previous in None      Next in None      

Question Number 196938 by sonukgindia last updated on 04/Sep/23

Answered by deleteduser1 last updated on 04/Sep/23

xy+yz+zx≤147(equality when x=y=z=+_− 7) (((x^2 +y^2 +z^2 )/3))≥(((x+y+z)/3))^2 ⇒3(147)≥(x+y+z)^2 ⇒−21≤(x+y+z)≤21 ⇒x+y+z−xy−yz−zx≥−147−21=−168 (equality when x=y=z=−7)

xy+yz+zx⩽147(equalitywhenx=y=z=+−7)(x2+y2+z23)⩾(x+y+z3)2⇒3(147)⩾(x+y+z)2⇒−21⩽(x+y+z)⩽21⇒x+y+z−xy−yz−zx⩾−147−21=−168(equalitywhenx=y=z=−7)

Terms of Service

Privacy Policy

Contact: info@tinkutara.com